7x+30=19x^2

Solution for 7x+30=19x^2 equation:

7x+30=19x^2

We move all terms to the left:

7x+30-(19x^2)=0

determiningTheFunctionDomain
-19x^2+7x+30=0

a = -19; b = 7; c = +30;
Δ = b2-4ac
Δ = 72-4·(-19)·30
Δ = 2329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{2329}}{2*-19}=\frac{-7-\sqrt{2329}}{-38}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{2329}}{2*-19}=\frac{-7+\sqrt{2329}}{-38}
$